## How many bit strings of length 10 contain an equal number of 0’s and 1’s?

(d) An equal number of 0s and 1s in a string of length 10 means that there are **five 0s and five 1s**.

## How many 10 digit bit strings are there?

The first digit can be any of 5 digits but the other two can be any of 10 digits so the answer is 5 · 10 · 10 = **500**.

## How many bit strings of length 4 are there?

How many bits string of length 4 are possible such that they contain 2 ones and 2 zeroes? Explanation: The strings are {**0011 0110 1001 1100 1010 and 0101**}. 4. If a bit string contains {0 1} only having length 5 has no more than 2 ones in it.

## How many binary strings of length 10 contain exactly 4 0s?

= (10 × 9 × 8 × 7)/4! = **210**. b) at most four 1s? We add up the number of bit strings of length 10 that contain zero 1s one 1 two 1s three 1s and four 1s.

## How many 10 bit strings contain 6 or more 1’s?

**386 strings**.

## How many bit strings of length 10 begin and end with a 1?

**256 bit strings**of length ten that begin and end with a 1.

## How many bit strings of length n contain exactly r 1s?

A bit string of length n with exactly r 1’s will have **exactly n−r 0’s**.

## How many bit strings contain exactly five 0s?

How many bit strings contain exactly five 0s and fourteen 1s if every 0 must be immediately followed by two 1s? What I need help with: For this question the answer is **126-bit strings**.

## How many bit strings of length 10 contain at least three 1s and at least three 0s?

**912 strings**of length 10 contain at least three 1s and at least three 0s.

## How many bit strings of length 7 are there?

c) How many bit strings of length seven contain three consecutive 0s? Let an denote the number of such strings of length n. 0 0 0 1 3 8 20 47 107 238 520 1121 2391 …. Hence there are a7 = **47 bit strings of length seven** that contain three consecutive 0s.

## How many bit strings of length four do not have two consecutive 1s explain by using appropriate tree diagram?

How many bit strings of length four do not have two consecutive 1s? However the correct solution turns out to be **8**.

## How many binary strings of length n which is not starting from 10 are possible?

So if you sum all of that up you get **512 strings** which makes sense because 210=1024..

## How many 19 bit strings contain at least 4 zeros?

(C) is similar to (b) but “at least four” means four or more. Thus you want to calculate the number of bit strings that have four five six … up to **10** ones then add these together (or is there an easier way to do it if we realize that at most three is the opposite of at least four?)

## How many 8 bit binary strings have exactly 3 zeros?

How many 8-bit strings contains three 0’s in a row and five 1’s? Answer = **6!/**5!

## How many 8 bit strings have weight 5 ie contain exactly five 1s and start with the sub string 101?

There are (53)=**10 eight**-bit strings of weight five starting with 101 (your A)

## How many strings are there of lowercase letters of length 4 or less?

**475 254 strings** (excluding the empty string)

## What is an 8 bit string?

**A byte** is a string of 8 bits.

## How many length 10 strings are there of the letters a B and C that contain exactly 4 as?

Thus our final answer is 1+8+40+160=**209 possible strings**.

## How many bit strings of length 8 either start with 01 or end with 01?

4 Answers. We interpret starts with 1 or ends in 01 as meaning that bit strings that satisfy both conditions qualify. By your correct analysis there are **27 bit strings** that start with 1.

## How many bit strings of length eight either start with the bits 11 or end with the bits 00?

The correct answer is “option **3**“.

## How many different bit strings are there of length 8 that contain the string 0000?

**128**.

## How many ternary string lengths exist?

Answer and Explanation: i) There are three choices for each digit in a ternary string so there are 315=**14** 348 907 3 15 = 14 348 907 ternary strings of length 15.

## How many bit strings are there of length 14 that have exactly five zeros?

How many bit strings contain exactly five 0s and 14 1s if every 0 must be immediately followed by two 1s? Since given bit string contains five 0s and fourteen1s so the required bit string length is **19**.

## How many strings can be formed by ordering the letters salespersons if no two s’s are consecutive?

possible strings of SALESPERSONS with no consecutive S’s. Thus there are **2 540 160 strings** of SALESPERSONS with no consecutive S’s..

## How many different bit strings of length seven are there end with 10?

I am thinking for the strings that start with 10 we would have 7−2=5 bits to choose so **32 possible bit strings** of length 7 that starts with 10.

## How many bit strings of length 12 contain an equal number of 0s and 1s?

Step 5. (d) An equal number of 0s and 1s in a string of length 12 means that there are **six 0s and six 1s**.

## How many permutations of the letter Abcdefgh are there?

Therefore there are **40320 permutation** in the letters “a b c d e f g h”.

## How many words of length 8 can you form which contain exactly one vowel?

The answer is **217×8×(51)**. This is because we can choose one vowel in (51) ways. The other 7 can be filled with 21 letters(consonants) with repitition.

## How many bit strings are there of length 6 or less?

**126 bit strings**of length six or less (excluding the empty string)

## How many different bit strings of length n are there?

Since a bit consists of either the number 1 or 0 there are only two ways that the first slot can be filled or 2n ways. Since there are eight bits the answer would be **28 or 256**.

## How many bit strings of length n have no consecutive bits that are equal?

There are **2n bit-strings** of length n. The number of bit-strings with NO 2 consecutive zeroes is =2n− (no of bit-strings with consecutive zeroes)

## How many 10 digit strings of 0’s and 1’s are there that do not contain any consecutive 0’s?

Answer: 10 digit strings of 0’s and 1’s that do not contain any consecutive 0’s are **144**.

## What are the possible number of binary codes can be generated using N number of bits?

…

Maximum Decimal Value for N Bits.

Number of Bits | Maximum States |
---|---|

32 |
4 294 967 296 (4 G) |

## How many bit strings of length 9 are there?

How many bit strings of length 9 contain exactly three 1s? 10∗10∗10∗96=**531441000** But then those first 1′s don’t necessarily have to be the first 3 digits. They can be elsewhere in the digit string as well.

## Counting bit strings

## What is a Bit String in Discrete Mathematics | Discrete Mathematics Bit String lecture in urduhindi

## Example n bit string without consecutive zero

## What Are Bit Strings?