# What Volume Of A 2.00 M Kcl Solution Is Required To Prepare 500. Ml Of A 0.100 M Kcl Solution?

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## How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution?

5) How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution? Need to add 1200 – 500 = 700 mL.

## What is the final volume of 0.10 m Naoh that can be prepared from 250 mL of 0.30 M Naoh?

750 mL

The answer is rounded to two sig figs. So you can decrease the concentration of 250 mL of sodium hydroxide solution from 0.30 M to 0.10 M by adding enough water to get its final volume to 750 mL .

## How would you make 1 liter of a 2 M KCl solution?

Step 2 To make a 2M aqueous solution of KCl dissolve 149.102 grams of KCl in some distilled deionized water. Then add more water to the flask until it totals 1 liter.

## What is the molarity of a solution containing 5.0 moles of KCl in 2.0 l of solution?

2.5M

M=5mol2L=2. 5mol/L. 5 m o l / L . Hence the correct option is A that is 2.5M .

## How many grams of potassium carbonate are needed to make 2.00 102 mL 200 mL of a 2.5 M solution?

70 g of potassium carbonate.

## What volume of water should be added to 2.6 g of KCl to make a 4m solution?

Question: 6. What volume of water should be added to 2.6 g of KCl to make a 4 M solution? 8.7ml Acid/Base: The Water Constant and pH Instructions: Determine if each solution is acidic basic or neutral.

## What volume of 2.5% m/v KOH can be prepared from 125 mL of a 5.0% KOH solution?

The short answer is that the volume of the target solution will be equal to 250 mL .

## What is the pH of 0.10 m NaOH?

13

NaOH is a strong base so this will produce 0.1mol/L of OH ions in solution. This will produce a pH of 13. Therefore the pH of 0.1 M NaOH solution is 13.

39.997 g/mol

## How many grams of KCl would you need to make a 1 Litre solution which is 0.1 m?

74.0 grams

The mass of a potassium atom is 39 amu and the mass of a chlorine atom is 35 amu. This means that KCl has a mass of 74 amu and one mole of KCl is 74 grams. To make a 1 M solution of KCl you would dissolve 74.0 grams in one liter of water.

## How do you make 1m solution of KCl?

For a 1 M solution of KCl dissolve 74.55 g of KCl in 900 mL of H2O. Make up the volume to 1 L with H2O and autoclave for 20 min on liquid cycle.

## How many moles of KCl are in 0.556 l of a 2.3 M KCl solution?

So in the first step were given 2.3 uh malaria T k c l. And we’re told that we have uh 0.556 leaders. So we multiply and we get a value of 1.3 moles.

## What is the molarity of a 2.0 L solution containing 5.0 moles of table salt?

Concentration = 2.5⋅mol⋅L−1 .

## What is the molarity m of a solution that contains 5.0 moles of solute in 2000 mL of solution?

The molarity of the solution is 5.1 mol/L .

## What is the molarity of a solution that contains 17g of NH3?

Sum = 17 g/mol

See also why do animals such as humans need levels of organization?

The moles of NH3 is: We know that the volume of the solution is 0.50 L. We can now calculate for molarity: The molarity of the NH3 solution is 2 M.

## How do you make 2M K2CO3?

(iii) 2M K2CO3 (Potassium Carbonate): Dissolve 276.41 g K2CO3 in 1000 ml distilled water. (iv) 0.25M Na2CO3 (Sodium Carbonate): Dissolve 26.5 g Na2CO3 in 1000 ml distilled water. (v) 1M CH3COOH (Acetic Acid 99.5% assay ρ = 1.05g/cm3): Dissolve 57.192 ml CH3COOH and make up the volume to 1000 ml with distilled water.

## How many grams of potassium carbonate do I need?

The mass of potassium carbonate needed is 69.1 grams.

## How many grams of potassium carbonate are needed to make 200 ml of a 2.5 M solution hint use molarity formula but you are solving for solute not molarity?

Hence 69 grams of potassium carbonate \$ {K_2}C{O_3} \$ are needed to make \$ 200{text{ }}mL \$ of a \$ 2.5{text{ }}M \$ solution.

56.1056 g/mol

## How many milliliters of a 25% m/v NaOH solution would contain 75 g of NaOH?

300 milliliters

It is used when the mass of the solute and the volume of the solution are known to us. In general it can be defined as the mass of solute dissolved in a 100 mL volume of solution. hence 300 milliliters of a \$25%\$ (m/v) NaOH solution would contain 75 g of NaOH.

## What is the name of Koh?

Potassium hydroxide/IUPAC ID
Potassium hydroxide solution (KOH aqueous) is a colourless inorganic liquid that acts as a strong base (alkali). KOH solution is also known as caustic potash or potash lye and has many different applications.

## What is the pH of 0.025 m NaOH?

12.40

This means that the 0.025 M NaOH solution will have a OH− concentration of 0.025 M. When we know the hydroxide ion concentration of a solution can can calculate its pOH and then its pH. The pH of the solution is 12.40.

## What is the pH of a 0.00001 M NaOH solution?

pH+pOH=14⇒pH=14-3=11.

## What is the mass of sodium hydroxide present in 500mL of 1M NaOH solution?

“What mass of solid NaOH is needed to make 500mL of 0.1M NaOH solution?” To make one mole NaOH solution dissolve 40 grams NaOH in 500mL of H2O.

32.065 u

5 mol L−1.

## What is the pH of 0.1 M KCl solution?

pH of KCl aqueous solution is 7 because in KCl both cation and anion are spectator ion which are not hydrolysed .

## What is the conductivity of 0.01 M KCl?

The specific conductance of a 0.01 M solution of KCl is 0.0014 ohm^-1 cm^-1 at 25^∘C .

## How many liters of nacl solution do you need if you want 2.5 m nacl and you use 25.0 g of nacl?

A 2.5 M solution is 2.5 moles per liter (Molarity is just the number of moles per liter). Therefore 0.5 L would contain 1.25 mol. Hence you would need 1.25 × 58.44 g = 73 g. Personally I prefer the first approach!

## What is 1M solution?

A molar solution is defined as an aqueous solution that contains 1 mole (gram-molecular weight) of a compound dissolved in 1 liter of a solution. In other words the solution has a concentration of 1 mol/L or a molarity of 1 (1M).

## How do you prepare standard KCl solution?

a) Place 2-3 g of AR potassium chloride (KCl) in a 50 ml beaker and dry in an oven for 3-5 hours at 105°C then cool to room temperature in a desiccator. b) Weigh 0.746 g of KCl into another 50 ml beaker. c) Dissolve the KCl in the beaker with good quality de-ionised water e.g. ‘Option water’.

## How do you calculate KCl mEq?

Step 3: 1 mEq KCl = 1/1000 x 74.5 g = 0.0745 g = 74.5 mg Step 4: 1 mEq KCl = 74.5 mg 1.5 g KCl = 1500 mg How many mEq in 1500 mg?

## How many liters of a 0.5 M sodium hydroxide solution would contain 2 moles of solute?

4 liters

4 liters of a 0.5M sodium hydroxide solution would contain two moles of solute.

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